The solution I went with is to walk the entire bank of batteries with their joltages and pair them up. At every step I can either form an incomplete candidate (Left x), or a complete candidate (Right (a, b)) if I already have a previous candidate.
50 lines
1.5 KiB
Haskell
50 lines
1.5 KiB
Haskell
module Main where
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import Data.Char (digitToInt)
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import Data.Either (rights)
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import Debug.Trace
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import System.Environment (getArgs)
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-- | A candidate is either a left-most number we've just selected, or
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-- a complete candidate represented as a pair.
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type Candidate = Either Int (Int, Int)
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main :: IO ()
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main = do
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input <- readFile . head =<< getArgs
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putStrLn $ "Part 1: " ++ show (part1 input)
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putStrLn $ "Part 2: " ++ show (part2 input)
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-- | Maintain a list of candidates (either partial, or complete) and
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-- then select the greatest one for each line.
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--
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-- Insight: By keeping a list of possible candidates we can always
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-- backtrack out of an accidental corner (like making a partial
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-- candidate of the last digit).
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part1 :: String -> Int
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part1 = sum . map (maximum . map combine . rights . foldl go [] . map digitToInt) . lines
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where
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go :: [Candidate] -> Int -> [Candidate]
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go [] x = pure $ Left x
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go (Left a : candidates') x
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| x > a = Left x : Right (a, x) : candidates'
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| otherwise = Right (a, x) : candidates'
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go candidates@(Right (a, b) : candidates') x
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| x > a = Left x : Right (a, x) : candidates
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| x > b = Right (a, x) : candidates'
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| otherwise = candidates
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combine :: (Int, Int) -> Int
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combine (a, b) = a * 10 + b
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part2 :: String -> Int
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part2 = error "Not implemented"
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testInput :: String
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testInput =
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unlines
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[ "987654321111111",
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"811111111111119",
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"234234234234278",
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"818181911112111"
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]
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