aoc-25

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109 KiB

Author	SHA1	Message	Date
Jacob Jonsson	7af90f9e9c	feat: solve day 5, part 2 Keeping the old solution for the ranges was too ineffective when it came to enumerating all contained integers, the amount of elements was too large to either expand the ranges into Sets or similar. However, it turned out (after some thinking) to be fairly straight-forward to check if consecutive ranges overlapped, and in that case merge them. The solution therefore now parses the ranges, sorts them on the first component and then merges them as far as possible. changes: JJ: M app/Day5.hs	10 hours ago
Jacob Jonsson	19e994ef71	feat: solve part 1 day 5	11 hours ago
Jacob Jonsson	8e780753c1	feat: solve day4 part 2 Part two is solved by repeatedly removing all free rolls until there are no more rolls to remove. When removing the rolls we keep a running count of how many rolls we've removed.	1 day ago
Jacob Jonsson	47259d1697	feat: solve day4 part 1 We look at each valid (having coordinates inside the grid) neighbor to a cell including a paper roll and then see if the neighbor contains a roll of paper or not. Finally we count the number of rolls, if it is less than 4 we can pick it.	1 day ago
Jacob Jonsson	19194b5d78	feat: solve part 2 day 3	2 days ago
Jacob Jonsson	249365968a	feat: implement day 3, part 1 The solution I went with is to walk the entire bank of batteries with their joltages and pair them up. At every step I can either form an incomplete candidate (Left x), or a complete candidate (Right (a, b)) if I already have a previous candidate.	2 days ago
Jacob Jonsson	3f0d19a5d1	feat: solve part 2 of day 2	4 days ago
Jacob Jonsson	2e8920cae1	feat: solve day2 part1	4 days ago
Jacob Jonsson	12d392e578	feat: solve day1	4 days ago
Jacob Jonsson	fd14a98915	chore: add scaffolding	4 days ago

10 Commits (7af90f9e9cb774e72b2cc723bb37ff329f87bb59)